Math, asked by ruchisinghunn, 1 year ago

A right angled triangle having hypotenuse 25cm and sides are in the ratio 3:4 is made to revolve about its hypotenuse. The volume of the double cone so formed is

Answers

Answered by josimagic
0

Here 3:4 is the ratio of the right angled triangle

so, 3x and 4x be th two sides,

(3x)^2 + (4x)^2 = 25

9x^2 + 16x^2=25

x=1, 3cm and 4 cm be the other two sides.

revolve about its hypotenuse height of cone is 4cm and base radius is 3cm

therefore volume of cone, V = 1/3(π x r^2 x h)

1/3(3.14 x 3^2 x 4)=37.714 cm^3


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