A right angled triangle having hypotenuse 25cm and sides are in the ratio 3:4 is made to revolve about its hypotenuse. The volume of the double cone so formed is
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Here 3:4 is the ratio of the right angled triangle
so, 3x and 4x be th two sides,
(3x)^2 + (4x)^2 = 25
9x^2 + 16x^2=25
x=1, 3cm and 4 cm be the other two sides.
revolve about its hypotenuse height of cone is 4cm and base radius is 3cm
therefore volume of cone, V = 1/3(π x r^2 x h)
1/3(3.14 x 3^2 x 4)=37.714 cm^3
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