A road roller is 140 cm long and its diameter is 84 cm.It takes 1000 complete revolutions to move once over to level the road.Find the cost of levelling the road at Rs. 50 per 100 sq. metres.
Answers
Answered by
1
This is very simple question
STEP 1 Use csa of the cylinder formula
STEP 2 multiply by 1000 because 1000 Revolution
STEP 3. Multiply by 50
Thats all !
Answered by
3
road roller is in the shape of a cylinder
length = h=140 cm
diameter = d== 84 cm
radius =r =d/2 =42cm
distance moves in one revolution= curved surface area of the cylinder
= 2×pi*r*h
area for 1000 complete revolutions= 1000*2*pi*rh
=1000*2*22/7*42*140
=1000*2*22*42*20 cm^2
=1000*2*22*42*20*1/100*1/100 m^2
=2848 m^2
100sq m road levelling cost =Rs50
2848m^2 road leveling cost = 2848*50/100
=Rs1424
length = h=140 cm
diameter = d== 84 cm
radius =r =d/2 =42cm
distance moves in one revolution= curved surface area of the cylinder
= 2×pi*r*h
area for 1000 complete revolutions= 1000*2*pi*rh
=1000*2*22/7*42*140
=1000*2*22*42*20 cm^2
=1000*2*22*42*20*1/100*1/100 m^2
=2848 m^2
100sq m road levelling cost =Rs50
2848m^2 road leveling cost = 2848*50/100
=Rs1424
mysticd:
ur welcome
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