Math, asked by Anonymous, 1 month ago

A road roller takes 750 complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is 84 cm and length is 1 m.​

Answers

Answered by sakash20207
13

given \: length \: of \: the \: roller  \\ = h  \  = 1m  \:  \\ diameter \: of the \: roller \:  =  \\ 84 \: cm \\ therefore \: \:  radius \: ofthe \: roller \:  \\  = r =  \frac{84}{2} cm \\  = 42cm \\  =  \frac{42}{100} m \\ given \: the \: roller \: takes \: 750 \\ complete \: revolutions \: to \: level  \\ \: the \: whole \: road \: . \\ therefore \: area \: of \: the \: road =  \\ 750 \times area \: covered \: in1 \: \\ revolution \: . = \\ 750 \times lateral \: surface \: area \\ of \: cylinder. \\  = 750 \times 2\pi \gamma h \\  = 750 \times 2 \times  \frac{22}{7}  \times  \frac{42}{100 }  \times 1 \\  = 750 \times 2 \times 22 \times  \frac{6}{100}  \times 1 \\  =  \frac{1500 \times 132}{100}  \\  = 15 \times 132 \\  = 1980 {m}^{2}

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Answered by deepika717171
3

HOPE THIS WILL HELPS YOU .

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