a rocket of mass 100 kg burns 0.1 kg of fuel per sec.if velocity of exhaust gas is 1 km/sec then it lifts with an acceleration of
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Answer:
The answer is 1 x 10 ^ -3 m/s ^ 2 .
Explanation:
Given data:
Mass (m) = 100 kg
Velocity (u) =1 km/sec
dm/dt = 0.1
1 - We know that
F = m/a
to find acceleration, first we nee to find force "F"
So,
F = u x dm/dt
= 1 x 0.1 = 0.1 N
2- Now calculate acceleration from above formula:
a = F/m
a = 0.1/100
a = 0.001 = 1 x 10 ^ -3 m/s ^ 2
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