Question

A rod 100 cm long and of 2cmxx2cm cross-section is subjected to a pull of 1000 kg force. If the modulus of elasticity of the materials is 2.0xx10^(6) kg//cm^(2), determine the elongation of the rod.

Answer 1

Elongation of the rod = 0.05 mm

Given:

A rod 100 cm long.

2cm x 2cm cross-section.

Subjected to a pull of 1000 kg force.

Modulus of elasticity of the materials is 2.0 x $10^6$kg/cm²

To find:

Elongation of the rod.

Formula used:

Elongation = $\frac{FL}{AE}$

Where         F = force.

                   L = Length of rod.

                   A = cross-section area.

                   E = Modulus of elasticity.

Explanation:

Elongation of the rod = $\frac{FL}{AE}$

Elongation of the rod = $\frac{1000\times 100}{10\times 10\times 2\times 10^6 }$

Elongation of the rod = $\frac{1}{10\times 10\times 20 }$

Elongation of the rod = 5×$10^-^4$ cm.

Elongation of the rod = 0.05 mm.

To learn more...

1)A uniform cylindrical rod of length l , cross sectional area a and yoings modulus y is acted upon by forces as shown. the elongation of the rod is.

https://brainly.in/question/3608270

2)A uniform heavy rod of weight W, cross-sectional area A and length L is hanging from a fixed support. Young's modulus of the material of the rod is Y. Neglect the lateral contraction. Find the elongation of the rod.

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