Question

A rod of length 1000 mm and co-efficient of linear expansion alpha = 10^(-4) per degree celsius is placed in horizontal smooth surface symmetrically between fixed walls separated by 1001 mm . The young's modulus of rod is 10^(11)N//m^(2). If the temperature is increased by 20^@C, then the stress developed in the rod is (in N//m^(2))

Answer 1

Explanation:

Δl due to temperature rise

=lαΔΘ

=(1000)(10^−4 )(20)

=2mm

But I mm is allowed (l000mm to 1001 mm)

∴

$Δl _{e} = 1mm$

Strees=Y×Strain

=(10^11 )(1mm/ 1000mm )

=10^8 N/m^2