a room is 11.5 M along and 6.3 M wide. it's floor is to be covered with rectangular tiles of side 23 CM by 9 CM. find the cost of tiles if one tiles cost rupees 10
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L= 11.5m
B= 6.3m
Area of floor= LxB= 11.5*6.3
=>72.45m^2
L=23cm=0.23m
B=9cm=0.09m
Area of 1 tile= LxB=0.23*0.09
=> 0.0207m^2
No. of tiles= 72.45/0.0207
=> 3,500 tiles
cost of one tile- Rs. 10
Total cost = 3500*10
=> Rs. 35000
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boredtroye561995:
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