A room is 16m long, 9m wide and 3m ig, it has two doors each door of dimensions 2m*1.5m and three windows each of dimension 1.6m*75cm find the cost of distempering the walls of the room from the inside at the rate of rs.50per square metre
Answers
b=9m
h=3m
TSA=2(lb+bh+lh)
2(144+27+48)
438m²
area of 3 windows=1.6×0.75×3
=3.660m²
area of 2 doors=2×1.5×2
=6m²
total area of room excluding doors and wall = 438-(6+3.660)
428.34m²
cost of distempering /m²=₹50
428.34×50
₹21417
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Cost of distempering the walls is Rs.7020
Step-by-step explanation:
Given:-A room of,
Length=16 m, Width=9 m, Height=3 m.
2 Doors of,
Length=2 m, Height=1.5 m.
3 Windows of,
Length=1.65 m,
Height=75 cm = 0.75 m.
Per square metre Cost of distempering the wall=Rs.50
To find:-Cost of distempering the walls at Rs.50 per square metre.
Solution:-
Area of 1 Door = = ------(Given)
Area of 1 Door = 3 square metre. ------------------(equation 1)
Area of 2 Doors = Area of 1 Door
Area of 2 Doors = = 6 -----------(from equation 1)
Area of 2 Doors = 6 square metre. -------(equation 2)
Area of 1 window =
Area of 1 window = 1.2 square metre. ---------(equation 3)
Area of 3 Windows =Area of 1 window 2
Area of 3 Windows = --------------(from equation 3)
Area of 3 Windows = 3.6 square metre. ------(equation 4)
Total area of walls
Total area of walls -------(given)
Total area of walls
Total area of walls = 150 square metre. ---------(equation 5)
Now,
Total Area to be distempered = Total area of wall - total area of 2 doors - total area of 3 windows
Total Area to be distempered = 150-6-3.6 ----(from equation 2,4,5)
Total Area to be distempered = 150-9.6
Total Area to be distempered = 140.4 square metre -------------(equation 6)
Cost of distempering the walls = Total area to be distempered Per square metre cost of distempering the walls
Cost of distempering the walls
Cost of distempering the walls = Rs.7020
Therefore, Cost of distempering the walls is Rs.7020.