A rope lies on table such that part of it lays over.the rope begins to slide when the length of hanging part is 25% of entire length .the coefficient of friction betwn rope and table is..?
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Let the coefficient of kinetic friction be k.
L/4 th part is hanging while 3L/4 th part is on the table.
So,
l/4*mg=k*3l/4 mg
Solving this we get k=1/3
Novil:
tq yl.
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