Question

A rope of length L is pulled by a constant force
F. What is the tension in the rope at a distance
x from the end where the force is applied
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Answer 1

Answer:

Let m be the mass per unit length of the rope.

for part PB, f−T=mxa.....(1)

for part PA, T=m(l−x)a...(2)

(1)+(2),f=mxa+mla−mxa=mla⇒

$a = \frac{f}{ml}$

now using (2), T=m(l−x) .

$\frac{f}{ml \: \: = } \frac{(1 - x)f}{1}$

Hope u r satisfied with my answer

;)