Question

A rope of mass 5 kg is moving vertically in vertical position with an upward force of 100n acting at the uppwr end and a downwards force of 70n acting at the lower end the tension at midpoint of the rope is

Answer 1

Hope it will help u

Answer 2

85 N is the tension at the rope's midpoint.

Explanation:

Given that,

Mass of the rope = 5 kg

Upward force = 100 N

Downward force = 70 N

To find,

Tension at the midpoint = ?

Procedure:

by using Newton's law, we will find acceleration

⇒ mg + 70 – 100 = ma

⇒ 50 + 70 – 100 = 5a

⇒ 20 = 5a

∴ a = 4 m/s^2

Assuming the tension at the midpoint be T and we will take the mass of the half rope i.e. 5/2 = 2.5 kg

by putting these values in Newton's IInd law, we get

Downward force + mass - Tension = mass * acceleration

⇒ 70 + 2.5 * g − T = 2.5 × 4

⇒ 70 + 25 - T = 10

⇒ T = 95 -10

∵ T = 85 N

Thus, 85 N is the tension at the midpoint of the rope.

Learn more: Calculate the tension

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