Question

A runner travels around rectangle track with length = 50 meters and width = 20 meters. After
travels around rectangle track two times, runner back to the starting point. Determine distance
and displacement.

Answer 1

Explanation:

Solution

Circumference of rectangle = 2(50 meters) + 2(20 meters) = 100 meters + 40 meters = 140 meters.

Travels around rectangle 2 times = 2(140 meters) = 280 meters.

Distance = 280 meter.

Displacement = 0 meter. (runner back to start point)

Average speed = distance / time elapsed = 280 meters / 100 seconds = 2.8 meters/second.

Average velocity = displacement / time elapsed = 0 / 100 seconds = 0.

Answer 2

Answer:

Circumference of rectangle = 2(50 meters) + 2(20 meters) = 100 meters + 40 meters = 140 meters.

Travels around rectangle 2 times = 2(140 meters) = 280 meters.

Distance = 280 m.

Displacement = 0 m. (the runner return to the starting point)

Hope it helps.........