English, asked by Missfoddie, 7 months ago

A sample of helium measuring 6L was kept at a pressure of 1.5atm. If the pressure is doubled what would be its new volume?

Answers

Answered by jothika132002
1

Answer:

30.5

Explanation:

V1 = 61

P1 = 1.5

P2 = 2P1 ( 2X1.5) =3

V2 =?

Using Boyle's law; V1P1 = V2P2

= 30.5

Therefore:

The new volume = 30.5

Answered by Anonymous
12

This may help you :)

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