A sample of helium measuring 6L was kept at a pressure of 1.5atm. If the pressure is doubled what would be its new volume?
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Answered by
1
Answer:
30.5
Explanation:
V1 = 61
P1 = 1.5
P2 = 2P1 ( 2X1.5) =3
V2 =?
Using Boyle's law; V1P1 = V2P2
= 30.5
Therefore:
The new volume = 30.5
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