Question

A says to B "my present age is five times your that age when I was as old as you are now." If the sum of their present ages is 48 years. Find their present ages

Answer 1

let A's age be "x" B's age be "y" x = 5y = x-5y=0 -eq 1 x+y=48 -eq2 subtract, -6y=-48 therefore, y = 8 and x = 40

Answer 2

Answer:

Step-by-step explanation:

Given :

A says to B “my present age is five times your that age when I was an old as you are now.

If the sum of their present ages is 48 years, find their present ages.​

Solution :

Statement 1 :

A says to B “my present age is five times your that age when I was an old as you are now.

Modifiedstatement :

A is 5 times as old as B,.

⇒ Present age of B = 5 times the present age of A

Let the age of A be x,

Let the age of B be y,.

⇒ y = 5x    ...(i)

Statement 2 :

If the sum of their present ages is 48 years, find their present ages.​

Modifiedstatement :

The total of their present age is 48.

⇒ x + y = 48,.

By substituting value of y in equation (i) , We get,.

⇒ x + (5x) = 48

⇒ 6x = 48

⇒ x =

⇒ x = 8,.

∴ The present age of A is 8 years.

By substituting value of x in (i),

We get,

⇒ y = 5x

⇒ y = 5 × 8

⇒ y = 40

∴ The present age of B is 40 years.

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