a scooter acquires as velocity of 36 km/h in 10 s just after the start .calculate the acceleration of the scooter?
rohit1834:
acc
Answers
Answered by
76
Your Answer ↓↓↓.
⇒ Initial velocity (u) = 0 (rest)
⇒ Final velocity (v)= 36km/ hr
Converting km/hr to m/sec.↓
v= 36×5/18
= 10 m/s.
Time ( t)=10s
Using ,
v= u+at
10 = 0+ a×10
10 = 10a
a= 10/10
a= 1 m/s²
The acceleration of the scooter is 1 m/s².
^_^ ^_^
#BE BRAINLY
⇒ Initial velocity (u) = 0 (rest)
⇒ Final velocity (v)= 36km/ hr
Converting km/hr to m/sec.↓
v= 36×5/18
= 10 m/s.
Time ( t)=10s
Using ,
v= u+at
10 = 0+ a×10
10 = 10a
a= 10/10
a= 1 m/s²
The acceleration of the scooter is 1 m/s².
^_^ ^_^
#BE BRAINLY
Answered by
39
from the equation of motion we get
v=u+at
initial velocity,u=0. (since body starts from rest)
final velocity v=36km/h=36x
5/18
therefore v=10m/s
t=10secs
v=u+at
V-U/t=a
10-0/10 =a
therefore a=1m/s2
hence the acceleration of the scooter is 1m/s2
v=u+at
initial velocity,u=0. (since body starts from rest)
final velocity v=36km/h=36x
5/18
therefore v=10m/s
t=10secs
v=u+at
V-U/t=a
10-0/10 =a
therefore a=1m/s2
hence the acceleration of the scooter is 1m/s2
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