Physics, asked by harshsavita21, 1 year ago

a scooter acquires as velocity of 36 km/h in 10 s just after the start .calculate the acceleration of the scooter?


rohit1834: acc

Answers

Answered by Ankit02
76
Your Answer ↓↓↓.

⇒ Initial velocity (u) = 0 (rest) 
⇒ Final velocity (v)= 36km/ hr 

Converting km/hr to m/sec.↓

v= 36×5/18
= 10 m/s. 

Time ( t)=10s
Using ,

 v= u+at
10 = 0+ a×10

10 = 10a
a= 10/10
a= 1 m/s²

The acceleration of the scooter is 1 m/s².

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Answered by yagnesh33
39
from the equation of motion we get

v=u+at

initial velocity,u=0. (since body starts from rest)

final velocity v=36km/h=36x

5/18
therefore v=10m/s

t=10secs

v=u+at

V-U/t=a

10-0/10 =a

therefore a=1m/s2

hence the acceleration of the scooter is 1m/s2

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