a Scooty was brought at rupees 42000 its value depreciated at the rate of 8%p.a find its value after one year
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Answered by
1
42000*0.08=3360
42000-3360=38640
42000-3360=38640
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4
Given that cost of the scooter = 42000. = > P = 42000
Given that Depreciation rate = 8% p.a.= > R = 8.
Given that n = 1 year.
We know that A = P(1 - r/100)^n
= 42000(1 - 8/100)^1
= 42000(92/100)
= 420 * 92
= 38640.
Therefore the value of scooter after 1 year = 38640 rupees.
Hope this helps!
Given that Depreciation rate = 8% p.a.= > R = 8.
Given that n = 1 year.
We know that A = P(1 - r/100)^n
= 42000(1 - 8/100)^1
= 42000(92/100)
= 420 * 92
= 38640.
Therefore the value of scooter after 1 year = 38640 rupees.
Hope this helps!
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