India Languages, asked by 7845487, 1 year ago

A scored 11 Percent marks and failed by 60 marks. B scored 28 Percent marks and obtained 8 marks more than those required to pass. The approximate pass Percentage is

Answers

Answered by Swarup1998
9

Answer:

The pass percentage is 26%.

Solution:

Let, total marks = x and pass marks = y

Step 1.

A scored 11% and failed by 60 marks.

Then marks obtained by A = pass marks - 60

or, 11x/100 = y - 60

or, x = (100y - 6000)/ 11 ..... (1)

Step 2.

B scored 28% and obtained 8 marks more than pass marks.

Then marks obtained by B = pass marks + 8

or, 28x/100 = y + 8

or, x = (100y + 800)/28

or, x = (25y + 200)/7 ..... (2)

Step 3.

Equating the left hand sides of (1) and (2) no. equations, we get

(100y - 6000)/11 = (25y + 200)/7

or, 7 (100y - 6000) = 11 (25y + 200)

or, 700y - 42000 = 275y + 2200

or, (700 - 275)y = 2200 + 42000

or, 425y = 44200

or, y = 104

From (2), we get

x = (25 * 104 + 200)/7

or, x = 400

Therefore, the pass percentage marks is

= (104 / 400) * 100 %

= 26%

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