A seconds' pendulum is taken on the surface ot moon where acceleration due to gravity is 1/6th of that of Earth. Will the time period of pendulum remain same or increase or decrease. Give a reason
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time period will increase because time period is inversely proportion to the square root of g so in moon g decrease so time period increase
since time period of second pendulum is 2s
so its new time period will be 2x 2.4 = 4.8
time period will increase because time period is inversely proportion to the square root of g so in moon g decrease so time period increase
since time period of second pendulum is 2s
so its new time period will be 2x 2.4 = 4.8
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