Question

. A semicircular conductor of radius R moved in uniform magnetic field B as
shown. Determine the emf induced in it. Which end is at higher potential?

Answer 1

Answer:

Correct option is

D

Bv (2R) sin θ

Join AB and then also make a segment A

′

B

′

.

There is no change in flux in the whole semicircular loop, thus no emf is generated in it. But a certain emf is induced in equivalent segment A

′

B

′

which is same as in between A and B.

Length of A

′

B

′

, L=2R

∴ EMF induced between A

′

and B

′

, E=Bv

⊥

L

E=B(vsinθ)(2R)

solution