Physics, asked by deenaapallan, 11 hours ago

. A semicircular conductor of radius R moved in uniform magnetic field B as
shown. Determine the emf induced in it. Which end is at higher potential?

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Answers

Answered by vikrantvikrantchaudh
0

Answer:

Correct option is

D

Bv (2R) sin θ

Join AB and then also make a segment A

B

.

There is no change in flux in the whole semicircular loop, thus no emf is generated in it. But a certain emf is induced in equivalent segment A

B

which is same as in between A and B.

Length of A

B

, L=2R

∴ EMF induced between A

and B

, E=Bv

L

E=B(vsinθ)(2R)

solution

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