A semicircular sheet of diameter 28 cm is bent into an conical cup . Find the depth and capacity of cup
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Diameter =d = 28 cm
Radius= r = 14 cm
Circumference of semi circle = πr
= (22/7) x 14
= 44 cm
so the circumference of base of cone
2πR = 44
R = 44 x (7/44)
R = 7 cm
The radius of semi circular sheet = slant height of conical cup
which is
l = 7 cm
As,
r2 + h2 = l2
142 + h2 = 72
196 – 49 = h2
h2 = 147
hence; h = 7√3 cm
depth of the conical cup= 7√3 cm
Capacity of cup = (1/3) πr2h
= (1/3) x (22/7) x 72 x 7√3
= 622.37 cm approx
________________________
HOPE , IT HELPS ... ✌️
______________________
______________________
Diameter =d = 28 cm
Radius= r = 14 cm
Circumference of semi circle = πr
= (22/7) x 14
= 44 cm
so the circumference of base of cone
2πR = 44
R = 44 x (7/44)
R = 7 cm
The radius of semi circular sheet = slant height of conical cup
which is
l = 7 cm
As,
r2 + h2 = l2
142 + h2 = 72
196 – 49 = h2
h2 = 147
hence; h = 7√3 cm
depth of the conical cup= 7√3 cm
Capacity of cup = (1/3) πr2h
= (1/3) x (22/7) x 72 x 7√3
= 622.37 cm approx
________________________
HOPE , IT HELPS ... ✌️
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