Question

A semicircular thin sheet of metal of radius 14 cm is bend and an open conical cup is made. Find the capacity of the cup

Answer 1

Answer:

Step-by-step explanation:

I hoped these W ill helps u

Change r= 14 all others would same

Answer 2

Answer:

$621.799 cm^3$

Step-by-step explanation:

Radius of semicircle = 14 cm

Circumference of base of cone = Length of arc of semicircle

$2 \pi r = \frac{1}{2}(2 \pi R)$

$2 r =14$

$r =7$

Slant height of cone = 14

$h^2 = l^2 - r^2$

$h=\sqrt{14^2-7^2}$

$h=12.124$

Volume of cone = $\frac{1}{3} \pi r ^2 h$

                           = $\frac{1}{3} \times 3.14 \times 7^2 \times 12.124$

                           = $621.799 cm^3$

Hence volume of cone is $621.799 cm^3$