Math, asked by tanukahlon2, 1 year ago

A sequence (an) is given by the formula an= 10 - 3n, show that sequence is an AP.

Answers

Answered by shambhavi20badoni
14

Answer:As it is given that

An=10 - 3n


Put n=1, we get

= 10-3*1

= 10-3 = 7

Put n =2 , we get

= 10-3*2

=10-6. =4

Put n=3, we get

= 10-3*3

= 10-9. = 1

Put n=4, we get

=10-3*4

=10-12 = -2

Hence, 7,4,1,-2 forms an A. P where common difference is 3..

Hope u get all of it..

Step-by-step explanation:


Answered by Tanvi14BTS
1

Answer: -3

Step-by-step explanation:

an = 10-3n

Put n value as 1

a1 = 10 - 3(1)

=10 - 3

= 7

Put n value as 2

an = 10 - 3(2)

= 10 - 6

= 4

Put n value as 3

an = 10 - 3(3)

= 10 - 9

= 1

As the common differences are same then they are in AP

d = a2 - a1

= 4 - 7

= -3

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