Question

A sequence is defined by the recursive function f(n + 1) = f(n) – 2.
If f(1) = 10, what is f(3)?

Answer 1

Answer:

A sequence is defined by the recursive function f(n + 1) = f(n) – 2.

f(1) = 10, f(3) = ?

Before finding f(3) we need to find f(2) because we are using recursive formula. also f(1) = 10 is given.

f(n + 1) = f(n) – 2, f(1) = 10

f(2) = f(1) - 2  (plug in 10 for f(1))

f(2) = 10 -2 =8, so f(2) =8

f(3) = f(2) -2 = 8 - 2 = 6

So f(3) = 6

The value of f(3) = 6

Answer 2

The value of the function is f(3)=6.

Step-by-step explanation:

Given : A sequence is defined by the recursive function $f(n+1)= f(n)-2$. If f(1) = 10.

To find : What is f(3) ?

Solution :

A sequence is defined by the recursive function $f(n+1)= f(n)-2$

For f(3), substitute n=2

i.e. $f(2+1)= f(2)-2$

Now, For f(2) substitute n=1 in function

i.e. $f(1+1)= f(1)-2$

$f(2)= 10-2$

$f(2)=8$

Substitute back,

$f(3)= 8-2$

$f(3)= 6$

Therefore, the value of the function is f(3)=6.

#Learn more

A sequence is defined by the recursive function f(n + 1) = –10f(n). If f(1) = 1, what is f(3)? 3 –30 100 –1,000

https://brainly.in/question/7128288