a shell of mass 50 kg is fired from a point on a level ground at an angle of 60° above the horizontal with a speed 200 m/s .neglecting air resistance ,calculate its kinetic energy of [i]its highest point of motion
[ii]a point of a horizontal distance of 1.1 km from the point of projection
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Answer:
i) KE at the highest position=1/2mu²cos²theta
=1/2*50*200²*cos²60
=25*40000*(1/2)²
=25*40000*1/4
=25*10000
=250000 J
ii)KE=1/2mv²
=1/2*50*200²
=25*40000
=1000000 J
Explanation:
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