A shell of mass 'M' moving with velocity 'V' suddenly explodes into two fragments. One of the mass 'm' is reduced to rest. Find the velocity of the other fragment.
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Answered by
3
whenever a body explodes it is due to its internal forces. So, no net external force acts on the body. Hence, momentum of the system remains conserved.
So,
initial momentum = final momentum
MV = (m×0) + (M-m)×v
MV = (M-m)v
v = MV/(M-m)
So,
initial momentum = final momentum
MV = (m×0) + (M-m)×v
MV = (M-m)v
v = MV/(M-m)
Answered by
1
By the principle of conservation of momentum
initial momentum=final momentum
or,MV=m(0)+(M-m)v
or,MV=(M-m)v
or,v=MV/(M-m)
Ans
initial momentum=final momentum
or,MV=m(0)+(M-m)v
or,MV=(M-m)v
or,v=MV/(M-m)
Ans
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