Question

A shephard has 200 sheep with him .Find the number of sheeps with him after 3 years if the increase is number of sheeps is 8 percent every year.​

Answer 1

Answer:

It is similar to the problem of simple interest

SI=

100

PRT

=

100

200×8×3

= 48 sheeps.

Total sheeps = 200+48

= 248 sheeps.

soluti

Answer 2

Answer:

GIVEN :-

P = 200

R = 8%

N = 3 years

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We know that,

A = P $\bigg( 1 + \dfrac {R}{100}\bigg)^N$

: $\implies$ 200 $\bigg( 1 +\dfrac {8}{100}\bigg)^3$

: $\implies$ 200 $\bigg( \dfrac {1}{1}+ \dfrac {2}{25}\bigg)^3$

: $\implies$ 200 $\bigg( \dfrac {25 +2}{25}\bigg)^3$

: $\implies$ 200 $\bigg( \dfrac {27}{25}\bigg)^3$

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: $\implies$ $\dfrac { 200 × 27 × 27 × 27}{ 25 × 25 × 25}$

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: $\implies$ $\dfrac{ 8 × 27 × 27 × 27 }{ 25 × 25}$

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: $\implies$ $\dfrac{157464}{625}$

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A = 251.94

A = 252⠀ ⠀ [maximum amount]

Therefore,A shephard will have 252 sheeps after 3 years.

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