a ship moving with a constant acceleration of 36km /h² in a fixed direction speeds up from 12km /h to 18 km /h .find the distance travelled by the ship in this period .
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Answer:
U= 12v- 18
a= 36v=u+ at
18= 12+ 36*t
6/36=t
t= 1/6
s=ut+1/2 at square
12*1/6+ 1/2 36* 1/6 square
= 2.50 hours .
Explanation:
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