Question

a ship moving with constant acceleration of km/h sq in a fixed direction speeds up from 12 km/h to 18 km/h. find the distance traversed by the ship in this period

Answer 1

Given,
u=12km/h
v=18km/h
a=1km/$h^{2}$
We kmow that,
$v^{2} - u^{2} =2as$
324-144=2s
180=2s
s=90km