a ship of mass 3 * 10^7 kg is at rest. It is then pulled to 3 metres by applying a force of 5*10^4 N. If friction of water is negligible , then find speed of the ship
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M=3*10^7
F=5*10^4 N
S=3m
U=0
V=?
We know,
F=M.A
5*10^4=3*10^7*a
a=5/3*10^-3
We know,
V²=U²+2as
V²=2*5/3*10-³ .3+0²
V²=10*10-³
V=√10²
V=.1m
ANSWER.
I HOPE IT'S HELP YOU.
MARK BRAINLIEST MY ANSWER DEAR FRIEND
THANKS.........
M=3*10^7
F=5*10^4 N
S=3m
U=0
V=?
We know,
F=M.A
5*10^4=3*10^7*a
a=5/3*10^-3
We know,
V²=U²+2as
V²=2*5/3*10-³ .3+0²
V²=10*10-³
V=√10²
V=.1m
ANSWER.
I HOPE IT'S HELP YOU.
MARK BRAINLIEST MY ANSWER DEAR FRIEND
THANKS.........
tinu21:
hey to do BRAINLIEST mark
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