A shopkeeper increases the selling price of his articles by 10% and then reduces it by 10%. Again he
does the same thing. Finally, the selling price of the articles comes down to Rs. 1944.75. What was the
original selling price?
Answers
Answer:
by taking SP as 100x the approximate answer is 1984 .
The original selling price of the article was 1984.43.
Step-by-step explanation:
Given:
The selling price of his articles are increased by 10% and then are reduced it by 10%.
Again The selling price of his articles are increased by 10% and then are reduced it by 10%.
Finally, the selling price of the articles is come down to Rs. 1944.75.
To Find: The original selling price of the article.
Formula Used:
When sell price Z is increased by k %, then the new selling price = Z (1+k/100)
When sell price Z is decreased by k %, then the new selling price = Z (1–k/100)
Solution:
Let the original selling price of the article was = Z
The selling price of his articles are increased by 10% = Z + Z x 10/100= 1.1 X
And then are reduced it by 10%. = 1.1 Z- 1.1 Z x 10/100 = 0.99 Z
Again The selling price of his articles are increased by 10% = 0.99 Z +0.99 Z.10/100= 1.089 Z
And then are reduced it by 10%. = 1.089 Z- 1.089 Z x 10/100 = 0.98 Z
Final selling price of article =0.98 Z
As given Final selling price of article Rs. 1944.75.
Therefore, 0.98 Z=1944.75
Z=1944.75/0.98
Z=1984.43
Thus, The original selling price of the article was 1984.43.