Math, asked by Aprajita6570, 1 year ago

A shopkeeper sells a saree at 8% profit and a sweater at 10% discount there by getting sum of rs 1008 if she had sold the saree at 10% profit and sweater at 8% discount she would have got rs1028. Find the cost price of the the saree and the list price of the sweater

Answers

Answered by jaymovaliya111pe8byg
7

answer: price of saree is 600 and sweater is 400

suppose price of saree is x and price of sweater is y

8% profit makes selling price of saree 100 + 8 % which is 108%x = 1.08*x

simillarly selling price of sweater is 100 - 10% = 0.9*y

so the equation is 1.08*x + 0.9*y = 1008

and second equation is 1.10*x + 0.92*y = 1028

solve these equations you will get your answer

if you face difficulty while solving these equations comment my answer.

All the best

Answered by Anonymous
74

\bold{\large{\underline{\underline{\sf{StEp\:by\:stEp\:explanation:}}}}}

Let the cost price of saree be Rs. 'x' and the list price of sweater be Rs. y.

Therefore,

\bold\green{Situation 1 -}

By selling a saree at 8 % profit and a sweater at 10 % discount, the shopkeeper gets Rs. 1008

⇒ 108x/100 + 90y/100 = 1008

⇒ 27x/25 + 9y/10 = 1008/1

Taking L.C.M. of the denominators and then solving it, we get.

54x + 45y = 50400 _________(1)

\bold\green{Situation 2 -}

by selling a saree at 10 % profit and a sweater at 8 % discount, the shopkeeper gets Rs. 1028.

 \sf{ \frac{110x}{100}  +  \frac{92y}{100} = 1028 }

 \sf{ \frac{11x}{10}  +  \frac{23y}{25}  = 1028}

Taking L.C.M. of the denominators and then solving it, we get.

⇒ 55x + 46y = 51400 _______(2)

Now, multiplying the equation (1) by 55 and (2) by 54, we get.

(54x + 45y = 50400)×55

= 2970x + 2475y = 2772000 _____(3)

(55x + 46y = 51400)×54

= 2970x + 2484y = 2775600 _____(4)

Now, subtracting (3) from (4), we get.

2970x + 2484y = 2775600

2970x + 2475y = 2772000

. - - - ___________________________

. 9y = 3600

___________________________

⇒ 9y = 3600

y = 3600/9

y = 400

Putting the value of y = 400 in (1), we get.

54x + 45y = 50400

54x + (45 × 400) = 50400

54x + 18000 = 50400

54x = 50400 - 18000

54x = 32400

.

x = 600

So, the cost price of a saree is Rs. 600 and the list price of a sweater is Rs. 400

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