A shopkeeper sells a saree at 8% profit and a sweater at 10% discount there by getting sum of rs 1008 if she had sold the saree at 10% profit and sweater at 8% discount she would have got rs1028. Find the cost price of the the saree and the list price of the sweater
Answers
answer: price of saree is 600 and sweater is 400
suppose price of saree is x and price of sweater is y
8% profit makes selling price of saree 100 + 8 % which is 108%x = 1.08*x
simillarly selling price of sweater is 100 - 10% = 0.9*y
so the equation is 1.08*x + 0.9*y = 1008
and second equation is 1.10*x + 0.92*y = 1028
solve these equations you will get your answer
if you face difficulty while solving these equations comment my answer.
All the best
Let the cost price of saree be Rs. 'x' and the list price of sweater be Rs. y.
Therefore,
By selling a saree at 8 % profit and a sweater at 10 % discount, the shopkeeper gets Rs. 1008
⇒ 108x/100 + 90y/100 = 1008
⇒ 27x/25 + 9y/10 = 1008/1
Taking L.C.M. of the denominators and then solving it, we get.
54x + 45y = 50400 _________(1)
by selling a saree at 10 % profit and a sweater at 8 % discount, the shopkeeper gets Rs. 1028.
Taking L.C.M. of the denominators and then solving it, we get.
⇒ 55x + 46y = 51400 _______(2)
Now, multiplying the equation (1) by 55 and (2) by 54, we get.
(54x + 45y = 50400)×55
= 2970x + 2475y = 2772000 _____(3)
(55x + 46y = 51400)×54
= 2970x + 2484y = 2775600 _____(4)
Now, subtracting (3) from (4), we get.
2970x + 2484y = 2775600
2970x + 2475y = 2772000
. - - - ___________________________
. 9y = 3600
___________________________
⇒ 9y = 3600
y = 3600/9
y = 400
Putting the value of y = 400 in (1), we get.
54x + 45y = 50400
54x + (45 × 400) = 50400
54x + 18000 = 50400
54x = 50400 - 18000
54x = 32400
.
x = 600
So, the cost price of a saree is Rs. 600 and the list price of a sweater is Rs. 400