Question

A shopkeeper sells pizzas by the slices charging Rs. 50 per slice. He has two types of pizzas one round with 30 cm diameter, divided into 10 pieces. Another pizza square in shape with side 30 cm divided in to 12 pieces.

Question-
Anjana bought the slice of round pizza and Sanjana opted for square slice. Who got a better deal? And by what quantity?

a) Sanjana, approximately 4 cm2
b) Anjana, approximately 4 cm2
c) Sanjana, approximately 5 cm2
d) Anjana, approximately 5 cm2

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The better deal is won by Sanjana and the quantity of her gain is approximate $5cm^{2}$. Hence the correct answer is option C [Sanjana, approximate $5cm^{2}$.

Given:

The shopkeeper sells the slices of the pizzas at the rate of Rs50 per slice.

He divides a round pizza with a diameter of 30cm into ten pieces.

He divides a square pizza with each side 30cm into twelve pieces.

To Find:

the better deal between Anjana and Sanjana who opted for a round pizza slice and a square pizza slice respectively and the quantity of gain between them.

Solution:

We can find the solution to this problem in the following way.

We shall use all the relevant formulae to arrive at the solution to this problem.

The area of the round pizza with a diameter of 30cm

$=\pi (\frac{30}{2} )^{2} \\=225\pi cm^{2}$

The area of the square pizza with each side 30cm

$=30\times 30\\=900cm^{2}$

The quantity of one slice of the round pizza bought by Anjana

$=\frac{225\pi }{10}\\=22.5\pi cm^{2}\\=70 cm^{2} [approximately]$

The quantity of one slice of the square pizza bought by Sanjana

$=\frac{900}{12}\\=75 cm^{2}$

We find that Sanjana has a better deal on pizza than Anjana.

The quantity of gain in the deal is

$=75-70\\=5 cm^{2}$

The required solution is that the better deal between Anjana and Sanjana who opted for a round pizza slice and a square pizza slice respectively is won by Sanjana and the quantity of her gain is approximate $5cm^{2}$Hence the correct answer is option C [Sanjana, approximate $5cm^{2}$.

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