Math, asked by suyashchiprikar4, 7 months ago

A shopkeeper sells two mobile phones for Rs. 3600 each. He gained a profit of 20% on one mobile phone and lost 20% on another mobile phone. What was the net profit or loss in the entire transaction ?​

Answers

Answered by nona123
1

Answer:

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Step-by-step explanation:

I will first find the %.

Now for 20% profit means article of 20 is sold at 24, and 20% loss means article of 30 sold at 24. So total CP is 50 and total SP will be 48. So there is loss of 4%.

In question given above total SP is 4800 but I have taken 48. Hence CP as per question should be 5000 (100 times of what I have initially taken). So total loss is 4% of 5000 that is 200.

These all are mental calculations, just by reducing problem to simple numbers that can be easily calculated mentally.

Let me know

Thanks.

Answered by TheProphet
5

Solution :

\underline{\bf{Given\::}}}

A shopkeeper sells two mobile phones for Rs.3600 each. He gained a profit of 20% & on other loss 20% on mobile phone.

\underline{\bf{Explanation\::}}}

\underbrace{\bf{1^{st}\:Case\::}}}

Using formula of the cost price as given gain % :

\boxed{\bf{Cost\:price\:(C.P.) = \dfrac{100}{100+gain(\%) } \times S.P. }}}

  • Selling price of one mobile = Rs.3600
  • Profit = 20%
  • Cost price = ?

A/q

\longrightarrow\sf{C.P.=\dfrac{100}{100 + 20} \times 3600}\\\\\\\longrightarrow\sf{C.P.= \dfrac{100}{120} \times 3600}\\\\\\\longrightarrow\sf{C.P. =\cancel{\dfrac{360000}{120}} }\\\\\\\longrightarrow\bf{C.P. = Rs.3000}

\underbrace{\bf{2^{nd}\:Case\::}}}

Using formula of the cost price as given loss % :

\boxed{\bf{Cost\:price\:(C.P.) = \dfrac{100}{100-loss(\%) } \times S.P. }}}

  • Selling price of one mobile = Rs.3600
  • Loss = 20%
  • Cost price = ?

\longrightarrow\sf{C.P.=\dfrac{100}{100 -20} \times 3600}\\\\\\\longrightarrow\sf{C.P.= \dfrac{100}{80} \times 3600}\\\\\\\longrightarrow\sf{C.P. =\cancel{\dfrac{360000}{80}} }\\\\\\\longrightarrow\bf{C.P. = Rs.4500}

Total cost price of both mobile phone = Rs.3000 + Rs.4500 = Rs.7500

Total selling price of both mobile phone = Rs.3600 + Rs.3600 = Rs.7200.

C.P > S.P.

⇒ Loss = Cost price - Selling price

⇒ Loss = Rs.7500 - Rs.7200

⇒ Loss = Rs.300

Now;

\mapsto\sf{Loss\:(\%) =\bigg( \dfrac{Loss}{C.P.} \times 100\bigg)\%}\\\\\\\mapsto\sf{Loss\:(\%) =\bigg( \dfrac{300}{7500} \times 100\bigg)\%}\\\\\\\mapsto\sf{Loss\:(\%) =\cancel{\bigg( \dfrac{30000}{7500} \bigg)} \%}\\\\\\\mapsto\bf{Loss\:(\%) = 4\:\%}

Thus;

The net loss % in the entire transaction will be 4% .

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