A shopkeeper sold mathematics books for Rs 108 on Monday and Rs 84 on Tuesday. What can
Be the maximum price of each book?
plz plz plz answer me fast
Answers
The shopkeeper sold math book for Rs 120 on Monday.
And the shopkeeper sold math book for Rs 64 on Tuesday.
We will calculate the maximum price by using LCM
The maximum price of the book is lcm(120,64)
120= 3 × 2 × 2 × 5 × 2
64= 2 × 2 × 2 × 2 × 2 × 2
LCM = 8 × 120 = 960
Therefore,
Answer: The maximum price of each book is Rs.960.
Answer:
According to the given problem, the shopkeeper sold mathematics books for Rs 108 on Monday and Rs 84 on Tuesday.
Hence , the maximum price of each book is Rs.12.
On Monday, the shopkeeper sold 108/12= 9 books
On Tuesday, the shopkeeper sold 84/12 = 7 books
Step-by-step explanation:
- The shopkeeper sold mathematics books for Rs 108 on Monday.
- He sold mathematics books for Rs 84 on Tuesday.
- To find the maximum price of each book,
we will have to find out the HCF of the amounts of 108 & 84.
HCF of 108 , 84:
108 = 2x2x3x3x3
84 = 2x2x3x7
HCF = 2x2x3 = 12
- Hence , the maximum price of each book is Rs. 12.
On Monday, the shopkeeper sold 108/12= 9 books
On Tuesday, the shopkeeper sold 84/12 = 7 books