Question

a shot put is a metallic sphere of radius 4.9cm if density of the metal is 7.8g/cubic cm. find the mass of shot put​

Answer 1

Given :

• A shot put is a metallic sphere of radius 4.9cm if density of the metal is 7.8g/cubic cm.

To Find :

• Mass of the shot put = ?

Solution :

• Radius of sphere = 4.9 cm
• Density = 7.8 g/cm³

Let's find the volume of sphere :

→ Volume of sphere = 4/3 πr³

→ Volume of sphere = 4/3 × 22/7 × 4.9 × 4.9 × 4.9

→ Volume of sphere = 4/3 × 22 × 0.7 × 4.9 × 4.9

→ Volume of sphere = 4/3 × 22 × 16.8

→ Volume of sphere = 1478.4 ÷ 3

→ Volume of sphere = 492.8 cm³

• Hence,the volume of sphere is 492.8 cm³.

Finding the mass of the shot put :

→ Density = Mass ÷ Volume

→ Density × Volume = Mass

→ Mass = 7.8 × 492.8

→ Mass = 3,843.84 g

→ Mass = 3.844 kg

• Hence,the mass of the shotput is 3.844 kg.

Answer 2

$\huge\bf\underline\mathfrak\blue{✫}$$\huge\bf\mathfrak{Required\: Answer}$

Mass of the shotput is 3.844kg.

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$\huge\bf\mathfrak{Explanation :}$

$\bf\underline\mathfrak\blue{Given :}$

➪ Radius = 4.9cm

➪ Density of metal = 7.8/cubic cm.

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$\bf\underline\mathfrak\blue{We\: know\: that :}$

• Volume of sphere = $\dfrac{4}{3}$ πr³

By using the formula,

☞︎︎︎ Volume of sphere = $\dfrac{4}{3}$ × $\dfrac{22}{7}$ × 4.9 × 4.9 × 4.9

☞︎︎︎ Volume of sphere = $\dfrac{4}{3}$ × 22 × 0.7 × 4.9 × 4.9

☞︎︎︎ Volume of sphere = $\dfrac{4}{3}$ × 22 × 16.8

☞︎︎︎ Volume of sphere = $\dfrac{1478.4}{3}$

.°. The volume of sphere is 492.8 cm³

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Now Let's find the mass of the Shotput,

$\bf\underline\mathfrak\blue{We\: know\: that :}$

• Density = $\dfrac{Mass}{Volume}$

• Mass = Volume × Mass

By using the formula,

☞︎︎︎ Mass = 7.8 × 492.8

☞︎︎︎ Mass = 3,843.84

☞︎︎︎ Round off value of 3,843.84 is 3.844 kg.

.•. 3.844Kg is the mass of the SHOTPUT.

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