Question

A simple interest on a certain si for 3 years and 6 months at 16% per annum is 3080. Find the sum.

please explain step by step ​

Answer 1

✪AnSwEr

${\tt{\red{\underline{\large{Given}}}}}$

• Simple intrest on acertain si for 3y and 6 month
• at 16% per annum 3080

${\sf{\green{\underline{\large{To\:find}}}}}$

• The sum

${\sf{\pink{\underline{\Large{Explanation}}}}}$

Simple intrest

$\tt{Amount}=\dfrac{P\times{R}\times{T}}{100}$

Here

• R=16%

• T=3y6m (Changing in years} =$3\frac{1}{2}=\frac{7}{2}$

• Amount =3080

$\tt{Amount}=\dfrac{P\times{R}\times{T}}{100}$

¶utting values

$\implies\tt{Amount}=\dfrac{P\times{R}\times{T}}{100}$

$\implies\tt{3080}=\dfrac{P\times{16}\times{\frac{7}{2}}}{100}$

$\implies\tt{3080}=\dfrac{P\times{16}\times{7}}{200}$

=>3080×200=16×7×P

=>p=616000/112

=>p=5500

Hence value of sum is 5500

Answer 2

S O L U T I O N :

$\bf{\large{\underline{\bf{Given\::}}}}}$

• Principal, (P) = ?
• Rate, (R) = 16%
• Time, (T) = 3 years + 6 month [6/12 = 1/2 years]
• Simple Interest = Rs.3080

$\bf{\large{\underline{\bf{To\:find\::}}}}}$

The sum.

$\bf{\large{\underline{\bf{Explanation\::}}}}}$

We know that formula of the S.I ;

$\boxed{\bf{S.I.=\frac{P\times R\times T}{100} }}}}$

A/q

$\longrightarrow\sf{3080=\dfrac{P\times \cancel{16}\times \frac{7}{\cancel{2}} }{100} }\\\\\\\longrightarrow\sf{3080=\dfrac{P\times 8\times 7}{100} }\\\\\\\longrightarrow\sf{3080=\dfrac{56P}{100}}\\\\\\\longrightarrow\sf{56P=3080\times 100}\\\\\\\longrightarrow\sf{P=\cancel{\dfrac{308000}{56} }}\\\\\\\longrightarrow\bf{P=Rs.5500}$

Thus;

The sum will be Rs.5500 .