Question

A simple pendulum is made by suspending a bob of mass 200 g by a string of length
1.2m.Calculate its time period .(g= 10ms-2)

Answer 1

Answer:

Calculate it's time period at a place where g= 10m/s² ... by suspending a bob of mass 500g by a string of length 1m. ... Time period (T)=2*pie(3.14)*square root of(l/g)

Explanation:

Calculate it's time period at a place where g= 10m/s² ... by suspending a bob of mass 500g by a string of length 1m. ... Time period (T)=2*pie(3.14)*square root of(l/g)

Answer 2

Answer:

mass=200g

gravity=10 m/s²

L=1m

So period (T)?

use this formula:

\begin{gathered}T=2\pi \sqrt{ \frac{L}{g} } \\\ T=2(3,14) \sqrt{ \frac{1}{10} } \\\ T=6,28. \sqrt{0,1} \\\ T=6,28(0,3) \\\ T=1,98 s\end{gathered}

T=2π

g

L

T=2(3,14)

10

1

T=6,28.

0,1

T=6,28(0,3)

T=1,98s

Explanation:

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