Rationalise the denominator of :
root over 32+ root over 48 by
root over 8 + root over 12
Answers
Answer:
The value of \frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}
8
+
12
32
+
48
is 2.
\sqrt{32}
32
can be simplified as \sqrt{16 \times 2}=4 \sqrt{2}
16×2
=4
2
Similarly,
\sqrt{48}
48
can be simplified as \sqrt{16 \times 3}=4 \sqrt{3}
16×3
=4
3
The same way,
\sqrt{8}
8
can be simplified as \sqrt{4 \times 2}=2 \sqrt{2}
4×2
=2
2
\sqrt{12}
12
can be simplified as \sqrt{3 \times 4}=2 \sqrt{3}
3×4
=2
3
As per given problem, \frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}
8
+
12
32
+
48
can be represented by using its simplified form,
Therefore,
\begin{gathered}\begin{array}{l}{=\frac{(4 \sqrt{2}+4 \sqrt{3})}{(2 \sqrt{2})+2 \sqrt{3}}} \\ \\ {=\frac{(4 \sqrt{2}+\sqrt{3})}{(2 \sqrt{2})+\sqrt{3}}} \\ \\ {=2}\end{array}\end{gathered}
=
(2
2
)+2
3
(4
2
+4
3
)
=
(2
2
)+
3
(4
2
+
3
)
=2
∴ The value is found to be 2.
Step-by-step explanation:
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Answer:
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