Question

A simple pendulum takes 1200 seconds to complete 60 oscillations. Calculate the time period and frequency of this pendulum

Answer 1

frequency-60/1200=0.02HZ
TP-20

Answer 2

Answer:

A simple pendulum takes 1200 seconds to complete 60 oscillations. The time period will be 0.05 Hz and the frequency of this pendulum will be 20s

Explanation:

• The number of oscillations completed per time is the frequency of oscillation. It can be obtained by the equation,  

        $Frequency = \frac{No\ of\ oscillations}{time\ taken}$

        The time period of an oscillation can be expressed as,

        $Time\ period = \frac{1}{frequency}$

• Let f be the frequency of oscillation, N be the number of oscillations completed in time t and T be the time period.

         So as per definition,

        $f = \frac{N}{t}$                            ...(1)

         and

        $T = \frac{1}{f}$

• In the question, it is given that,

        N   $=60$

         t   $=1200s$

• Then using equation(1),

         f = $\frac{60}{1200} =0.05 Hz$

         T = $\frac{1}{0.05}= 20s$