Physics, asked by kaarbhiala0xmi, 1 year ago

A simple pendulum with bob of mass m and conducting wire of length L swings(is hanging ) under gravity thro' an angle 2theetha. The earth's magnetic feild component in the direction perpendicular to swing is B. the max potential diff induced across pendulum is?

Answers

Answered by kvnmurty
66
Area covered by the pendulum = radius * angle covered
                     A = L * 2θ
Magnetic field= B (perpendicular to the plane of the swing)

Magnetic flux = φ = B * area = 2 B L θ
The time period of the pendulum = T = 2π * √(L/g)
       Frequency of pendulum swing = f = 1/2π  * √(g/L)

Potential difference induced between the ends of the pendulum rod/wire
 = V = - dφ/dt = - φ * f = - 1/2π  * 2 BL θ * √(g/L)
       = - (Bθ/π) √(Lg)

kvnmurty: click on red heart thanks above pls
Answered by Anonymous
1

Answer:

hope you understand

Explanation:

thank you

Attachments:
Similar questions