Question

(a) sin 15° [NCERT)​

Answer 1

sin 15° = sin(45°-30°)

           = sin 45°×cos 30°- cos 45°×sin 30°[sin(A-B)=sinAcosB - cosAsinB]

           = 1/√2×√3/2 - 1/√2×1/2

           = √3/2√2 - 1/2√2

           = √3-1/2√2

Answer 2

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