Question

a sliver coin weight 5.4 gram (avagradro=108) find the number of sliver atoms in the coin?​

Answer 1

Answer:

3.011 * $10^{22}$ Atoms

Explanation:

Molar mass of silver = 108g

Given mass = 5.4g

No. of Moles = $\frac{5.4 }{108}$

No. of Moles = 0.05

No. of Atoms = 6.022*$10^{23}$ * No. of Moles

No. of Atoms = 6.022 *$10^{23}$ * 0.05

∴No. of Atoms = 3.011 *$10^{22}$