A small quantity of light green coloured substance is heated in the beginning it loses some water and then suffocating gas is evolved and a red residue is left behind. Answer the following Name the red residue and write its formula Name the suffocating gas and write its formula Name the light green coloured substance and formula What type of reaction
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Answered by
42
Name the red residue and write its formula:
Name: iron(III) oxide
Formula: Fe2O3
Name the suffocating gas and write its formula:
Name: sulfur dioxide and fumes of sulfur trioxide
Formula: SO2 and SO3
Name the light green coloured substance and formula:
Name: iron(II) sulfate
Formula: FeSO4
Type of reaction: Decomposition
Note:
The equation can be written as:
2 FeSO4 → Fe2O3 + SO2 + SO3
Name: iron(III) oxide
Formula: Fe2O3
Name the suffocating gas and write its formula:
Name: sulfur dioxide and fumes of sulfur trioxide
Formula: SO2 and SO3
Name the light green coloured substance and formula:
Name: iron(II) sulfate
Formula: FeSO4
Type of reaction: Decomposition
Note:
The equation can be written as:
2 FeSO4 → Fe2O3 + SO2 + SO3
Answered by
12
The red residue is Ferric oxide or Iron oxide(III) oxide.
The formula of ferric oxide is Fe₂O₃.
The suffocating gas evolved is Sulphur dioxide and some fumes of Sulphur trioxide.
The formula of Sulphur dioxide is SO₂.
The light green coloured substance is Ferrous Sulphate or Iron(II) sulphate.
Formula is FeSO₄.
The reaction involved is known as displacement reaction.
2FeSO₄(s) → Fe₂O₃(s) + SO₂(g) + SO₃(g)
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