Question

A solenoid with N loops of wire tightly wrapped around an iron core is carrying an electric current I. If the current through this solenoid is reduced to half, then what change would you expect in inductance L of the solenoid​

Answer 1

Answer:

No Change

Because The inductance L did not depend upon current

L=UoNA/L

This is the formula of inducatnce L

Answer 2

If the current through this solenoid is reduced to half there will be no change in inductance, Inductance remains the same.

• The formula for calculating the self-inductance of the solenoid is $L = u_{o} \frac{N^{2} }{e}.A$, where N is the number of loops, and A is the area of cross-section.
• From the above-mentioned formula we can observe that the inductance of the solenoid is not dependent on the current passing through it. Hence, any change in current won't affect the inductance of the solenoid.

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