Question

A solid cube is at temperature t kelvin if this cube is cut into two equal halves then the ratio of energy emitted by per second by complete cube to that of half cube will be

Answer 1

Answer:

Explanation:

hope now it is clear to you

Answer 2

The ratio of energy emitted by per second by complete cube to that of half cube will be 3:4

We know that for a sphere of radius R, and surface area A at temperature T K, its power is represented as

P = eσAT⁴,

A = 4ПR²

When the sphere is cut into half,

new area (A') becomes half of the previous A along with one circular area.

So, A' = (1/2)(4ПR²) + ПR²                     [Area of a circle is ПR²]

A' = 3ПR²

We need to calculate A'/A.

A'/A = (3ПR²)/(4ПR²)

A'/A = 3/4

Thus the ratio is 3:4.