Math, asked by simantinibhatta, 1 year ago

A solid cube is cut into two cuboids of equal volumes. find the ratio of the total surface area of the given cube and that of one of the cuboids

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Answered by Anonymous
21

AnswEr:

Let the edge of the solid cube be a units. Since the cube is cut into two cuboid of equal volumes.

Therefore, the \sf\underline{dimensions} of each of the cuboid are :

  • Length = a units
  • Breadth = a units
  • Height = a/2 units

________________________

Now, \qquad\tt{S=Total\:surface\:area\:of\:cube=6a^2\:sq.\:units}

\sf{S}_{1} = Total surface area of one cuboid

 =  \tt \: 2(a \times a + a \times  \dfrac{a}{2}  +  \dfrac{a}{2}  \times a) \\  \\  \tt = 4 {a}^{2} sq. \: units

\huge\star \bf\underline{Required\:ratio:-}

\tt{S:}\tt{S}_{1}

= \tt{6a^2:4a^2}

= \underline\mathfrak{3:2}

#BAL

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