a solid cube of side 12 cm is cut intoeight cubes of equal area . what will be the size of new cube. also find the ratio btn their surface areas
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Side (a) of cube = 12 cm
Volume of cube = (a)3 = (12 cm)3 = 1728 cm3
Let the side of the smaller cube be a1.
Volume of 1 smaller cube
⇒ a1 = 6 cm
Therefore, the side of the smaller cubes will be 6 cm.
Ratio between surface areas of cubes
Therefore, the ratio between the surface areas of these cubes is 4:1.
Hope this helps!
Volume of cube = (a)3 = (12 cm)3 = 1728 cm3
Let the side of the smaller cube be a1.
Volume of 1 smaller cube
⇒ a1 = 6 cm
Therefore, the side of the smaller cubes will be 6 cm.
Ratio between surface areas of cubes
Therefore, the ratio between the surface areas of these cubes is 4:1.
Hope this helps!
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i) side of the big cube = A = 12cm
number of small cubes made by big cube = n= 8
let side of the small cube = a cm
ii)volume of the each small cube(a³) = volume of big cube /n
= A³/n
=(12*12*12)/8
=216
a³ = 6³
a= 6cm
iii)surface area of the big cube = 6A²= 6*(12)²= 864 cm²---(3)
iv) surface area of the small cube = 6a²= 6*6²=216cm²---(4)
v) ratio = (3)/(4) = 864/216 =4/1
=4:1
ratio =
number of small cubes made by big cube = n= 8
let side of the small cube = a cm
ii)volume of the each small cube(a³) = volume of big cube /n
= A³/n
=(12*12*12)/8
=216
a³ = 6³
a= 6cm
iii)surface area of the big cube = 6A²= 6*(12)²= 864 cm²---(3)
iv) surface area of the small cube = 6a²= 6*6²=216cm²---(4)
v) ratio = (3)/(4) = 864/216 =4/1
=4:1
ratio =
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