A solid metallic sphere of diameter 21cm is melted and recast into a number of smaller cones, each of diameter 3.5cm and height 3cm. find the number of cones so formed.
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Solution:-
Diameter of the sphere = 21 cm
So, radius of sphere = 21/2
Radius of sphere = 10.5 cm
Volume of sphere = 4/3πr³
= 4/3*22/7*10.5*10.5*10.5
Volume of sphere = 4851 cu cm
Diameter of cone = 3.5 cm
So, radius of cone = 3.5/2
Radius of cone = 1.75 cm
Volume of cone = 1/3πr²h
= 1/3*22/7*1.75*1.75*3
Volume of cone = 9.625 cu cm
Number cones formed = 4851/9.625
Number of cones formed = 504
Answer.
Diameter of the sphere = 21 cm
So, radius of sphere = 21/2
Radius of sphere = 10.5 cm
Volume of sphere = 4/3πr³
= 4/3*22/7*10.5*10.5*10.5
Volume of sphere = 4851 cu cm
Diameter of cone = 3.5 cm
So, radius of cone = 3.5/2
Radius of cone = 1.75 cm
Volume of cone = 1/3πr²h
= 1/3*22/7*1.75*1.75*3
Volume of cone = 9.625 cu cm
Number cones formed = 4851/9.625
Number of cones formed = 504
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