Question

a solid object has a weight of 5N. When it is submerged in water, it weighs 3.5N. Find the density of the object. ​

Answer 1

♊♊YOUR ANSWERS♍♍

✍ 3333.33 kg/m³

════════════════════

EXPLANATION —

↪Actually welcome to the concept of Fluid Mechanics

Apparent weight (W') = Actual weight (W) - Buoyancy (B)        

 where W = pgV & B = (pw) gV

pw = density of water i. e 1000

⇒5 = 3.5 - B

⇒B = 1.5

⇒(pw) gV = 1.5

⇒1000 × 10 × V = 1.5

⇒V = 1.5/10⁴ = 0.00015 m³

Now in air

⇒mg = 5

⇒m = 1/2 = 0.5

Density of Body

⇒d = m/v = 0.5/0.00015 = 3333.33 kg/m³

╒══════════════════════╕

‌ ‌‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ Thanks‌ ,hope you like it ! ‌ ‌ ‌‌ ‌ ‌

╘══════════════════════╛

Answer 2

Answer:

3.333kgm^-3

Explanation:

Apparent weight = Actual wt - up thrust

mass =pv where p is density of water and v is volume

Apparent weight is equal to actual wt - thrust

Apparent weight is equal to 3.5 Newton actual weight is equal to 5 Newton then upthrust is equal to 1.5 Newton

weight is equal to density into volume into acceleration due to gravity

density of water given one gram per centimetre cube and volume is capital v

and acceleration due to gravity is 10 Newton and weight of water is equal to 1.5 Newton upthrust is equal to wt of fluid displaced

here we find that v

is equal to 0.00015 metre cube

wt of object in air 5 Newton so here we

find that mass is equal to 1 by 2 kg

density is equal to mass by volume and answer is 3.333×10^3 kg per metre cube