Question

A solid of density
sooo kg/m3
weign 0.5kgf
in air. It is
completely immersed in a liquid of
density 800 kg/m3. calculate
apparent weight of the
weight of the solid
in
liquid. ​

Answer 1

Answer:

it's not sooo it is 5000

Step-by-step explanation:

question is mistake

Answer 2

Step-by-step explanation:

ANSWER

Density ρ = 5000 kg/m

3

Weight = 0.5 kg f in air

mass M = 0.5 kg

Volume V = M / ρ

= 0.5 / 5000 = 10

−4

m

3

mass of water displaced = V

∗

density of water

= 10

−4

∗1000 = 0.1 kg

Apparent weight = wt in air - wt of water displaced

= 0.5 kg f - 0.1 kg f

= 0.4 kg f

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